06.28.05
Determinants and the cross product
I haven’t been talking about math yet in this blog, so now it’s time to start. Here’s an interesting little tidbit I realized during teaching this week. I was telling my students about the cross product of vectors, and defined it as a determinant:

where as usual
are the standard unit vectors in 3-space. Now, the cool thing about this definition is that it shows immediately why
is perpendicular to both a and b. For that, one simply has to check that the dot product of it with each of them is 0. But the dot product with, say, a amounts to computing the determinant:

which of course is zero since two rows of the determinant are the same. Now, one my students asked me: Well, what about other dimensions? I was about to give them the usual answer about there being a mysterious reason why this would work only in dimension 3, but then I realized that in fact this works in all dimensions. If you have n-1 vectors in dimension n, then you can immediately produce a vector perpendicular to them as an n by n determinant:

The exact same reasoning shows that this vector is perpendicular to all the n-1 vectors comprising the rows of this determinant. An amusing special case is when n=2, in which case we get that the vector in the plane perpendicular to the vector
is none other than ! So clearly the magic of the cross product is not simply in it being perpendicular to the original vectors.
It’s stuff like that that makes me love teaching math!
Later
Rethemniotis. said,
July 14, 2005 at 2:35 pm
Poly endiaferon Charilae. Eidika h genikeush se n-diastaseis.
Geia xara,
X.
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