06.28.05
Determinants and the cross product
I haven’t been talking about math yet in this blog, so now it’s time to start. Here’s an interesting little tidbit I realized during teaching this week. I was telling my students about the cross product of vectors, and defined it as a determinant:

where as usual
are the standard unit vectors in 3-space. Now, the cool thing about this definition is that it shows immediately why
is perpendicular to both a and b. For that, one simply has to check that the dot product of it with each of them is 0. But the dot product with, say, a amounts to computing the determinant:

which of course is zero since two rows of the determinant are the same. Now, one my students asked me: Well, what about other dimensions? I was about to give them the usual answer about there being a mysterious reason why this would work only in dimension 3, but then I realized that in fact this works in all dimensions. If you have n-1 vectors in dimension n, then you can immediately produce a vector perpendicular to them as an n by n determinant:

The exact same reasoning shows that this vector is perpendicular to all the n-1 vectors comprising the rows of this determinant. An amusing special case is when n=2, in which case we get that the vector in the plane perpendicular to the vector
is none other than ! So clearly the magic of the cross product is not simply in it being perpendicular to the original vectors.
It’s stuff like that that makes me love teaching math!
Later